Assume that
x is an eventually positive solution of (
1.1) that satisfies (
3.4). Similar analysis to that in Zhang
et al. ([
3], Lemma 2.3) leads to the conclusion that, for all
\(t\geq t_{1}\), there exist two possible cases (1) and (2) (as those in the proof of Theorem
3.1), where
\(t_{1}\geq t_{0}\) is sufficiently large. First, assume that case (1) holds. Defining the function
ω by (
3.5) and proceeding as in the proof of Theorem
3.1, we arrive at inequality (
3.6). Multiplying (
3.6) by
\(H(t,s)\) and integrating the resulting inequality from
\(t_{1}\) to
t, we obtain
$$\begin{aligned} & \int_{t_{1}}^{t}H(t,s)\rho(s)q(s)\,\mathrm{ d}s\\ &\quad\leq H(t,t_{1})\omega(t_{1}) + \int_{t_{1}}^{t} \biggl[\frac{\partial H(t,s)}{\partial s}+h(s)H(t,s) \biggr]\omega(s)\,\mathrm{ d}s \\ &\qquad{}- \int_{t_{1}}^{t}\frac{p-1}{2}M H(t,s) g'(s)g^{n-2}(s)\frac{\omega^{p/(p-1)}(s)}{(\rho (s)a(s))^{1/(p-1)}}\,\mathrm{ d}s \\ &\quad\leq H(t,t_{1})\omega(t_{1}) + \int_{t_{1}}^{t}\frac{\varrho_{+}(t,s)}{\rho(s)}\bigl(H(t,s) \bigr)^{(p-1)/p}\omega (s)\,\mathrm{ d}s \\ &\qquad{}- \int_{t_{1}}^{t}\frac{p-1}{2}M H(t,s) g'(s)g^{n-2}(s)\frac{\omega^{p/(p-1)}(s)}{(\rho (s)a(s))^{1/(p-1)}}\,\mathrm{ d}s. \end{aligned}$$
Let
$$C^{p/(p-1)}:=\frac{p-1}{2}M H(t,s) g'(s)g^{n-2}(s) \frac{\omega^{p/(p-1)}(s)}{(\rho(s)a(s))^{1/(p-1)}} $$
and
$$D^{1/(p-1)}:=\frac{2^{(p-1)/p}(p-1)^{1/p}\varrho_{+}(t,s)(a(s)\rho (s))^{1/p}}{pM^{(p-1)/p}\rho(s)(g'(s)g^{n-2}(s))^{(p-1)/p}}. $$
Using the following inequality (a variation of the well-known Young inequality)
$$ \frac{p}{p-1}CD^{1/(p-1)}-C^{p/(p-1)}\leq \frac{1}{p-1}D^{p/(p-1)}, $$
(4.3)
where
\(p>1\),
\(C\geq0\), and
\(D\geq0\), we conclude that
$$\begin{aligned} &\frac{\varrho_{+}(t,s)}{\rho(s)}\bigl(H(t,s)\bigr)^{(p-1)/p}\omega(s) -\frac{p-1}{2}M H(t,s) g'(s)g^{n-2}(s) \frac{\omega^{p/(p-1)}(s)}{(\rho(s)a(s))^{1/(p-1)}} \\ &\quad\leq\frac{2^{p-1}}{p^{p}}\frac{a(s)(\varrho_{+}(t,s))^{p}}{(M g'(s)g^{n-2}(s)\rho(s))^{p-1}}. \end{aligned}$$
Hence, we have
$$\begin{aligned} \frac{1}{H(t,t_{1})} \int_{t_{1}}^{t} \biggl[H(t,s)\rho(s)q(s) -\frac{2^{p-1}}{p^{p}}\frac{a(s)(\varrho_{+}(t,s))^{p}}{(M g'(s)g^{n-2}(s)\rho(s))^{p-1}} \biggr] \,\mathrm{ d}s \leq \omega(t_{1}), \end{aligned}$$
which contradicts (
4.1). Assume now that case (2) holds and define the function
v as in (
3.8). As in the proof of Theorem
3.1, we obtain (
3.16). Multiplying (
3.16) by
\(K(t,s)\) and integrating the resulting inequality from
\(t_{1}\) to
t, we have
$$\begin{aligned} & \int_{t_{1}}^{t} K(t,s) \biggl[q(s) \biggl( \frac{\lambda g^{n-2}(s)}{(n-2)!} \biggr)^{p-1}-\frac{r(s)}{a(s)\delta ^{p-1}(s)E(t_{0},s)} \biggr] \,\mathrm{ d}s \\ &\quad\leq K(t,t_{1})v(t_{1})+ \int_{t_{1}}^{t}\frac{\partial K(t,s)}{\partial s}v(s)\,\mathrm{ d}s - \int_{t_{1}}^{t}(p-1) K(t,s)\frac{(-v(s))^{p/(p-1)}}{a^{1/(p-1)}(s)}\,\mathrm{ d}s \\ &\quad= K(t,t_{1})v(t_{1})- \int_{t_{1}}^{t}\zeta(t,s) \bigl(K(t,s) \bigr)^{(p-1)/p}v(s)\,\mathrm{ d}s - \int_{t_{1}}^{t}(p-1) K(t,s)\frac{(-v(s))^{p/(p-1)}}{a^{1/(p-1)}(s)}\,\mathrm{ d}s. \end{aligned}$$
Let
$$C^{p/(p-1)}:=(p-1) K(t,s)\frac{(-v(s))^{p/(p-1)}}{a^{1/(p-1)}(s)} \quad \mbox{and}\quad D^{1/(p-1)}:=\frac{(p-1)^{1/p}\zeta(t,s)a^{1/p}(s)}{p}. $$
Using inequality (
4.3), we obtain
$$\begin{aligned} &\int_{t_{1}}^{t} \biggl[ K(t,s)q(s) \biggl( \frac{\lambda}{(n-2)!}g^{n-2}(s) \biggr)^{p-1}-\frac {K(t,s)r(s)}{a(s)\delta^{p-1}(s)E(t_{0},s)}-\frac{a(s)(\zeta(t,s))^{p}}{p^{p}} \biggr] \,\mathrm{ d}s\\ &\quad \leq K(t,t_{1})v(t_{1})< 0, \end{aligned}$$
which contradicts (
4.2). This completes the proof. □