Firstly, we prove (
2.2). Note that for all
\(\varepsilon>0\)
$$\begin{aligned}& \sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2 } E \Bigl\{ \max_{1\le k \le n} |S_{k}|-\varepsilon n^{\alpha}\Bigr\} _{+}^{\gamma}\\& \quad= \sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2 }\int _{0}^{\infty}P \Bigl(\max_{1\le k\le n}|S_{k}|- \varepsilon n^{\alpha}>t^{1/\gamma} \Bigr)\,dt \\& \quad= \sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2 }\int _{0}^{n^{\gamma\alpha }} P \Bigl(\max_{1\le k\le n}|S_{k}|- \varepsilon n^{\alpha}>t^{1/\gamma } \Bigr)\,dt \\& \quad\quad{} + \sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2 }\int _{n^{\gamma\alpha }}^{\infty}P \Bigl(\max_{1\le k\le n}|S_{k}|- \varepsilon n^{\alpha}>t^{1/\gamma} \Bigr)\,dt \\& \quad\le \sum_{n=1}^{\infty}n^{\alpha p-2}P \Bigl(\max_{1\le k\le n}|S_{k}|>\varepsilon n^{\alpha}\Bigr) \\& \quad\quad{}+\sum_{n=1}^{\infty}n^{\alpha(p-\gamma)-2}\int _{n^{\gamma\alpha }}^{\infty}P\Bigl(\max_{1\le k\le n}|S_{k}|>t^{1/\gamma} \Bigr)\,dt. \end{aligned}$$
Hence by Theorem 2.1 of Qiu
et al. [
11], in order to prove (
2.2), it is enough to show that
$$\sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2 }\int _{n^{\gamma\alpha }}^{\infty}P \Bigl(\max_{1\le k\le n}|S_{k}|>t^{1/\gamma} \Bigr)\,dt< \infty. $$
Choose
q such that
\(1/(\alpha p)< q<1\).
\(\forall j\ge1\),
\(t>0\), let
$$\begin{aligned}& X_{j}^{(t,1)}=-t^{q/\gamma}I\bigl(X_{j}< -t^{q/\gamma} \bigr)+X_{j} I\bigl(|X_{j}|\le t^{q/\gamma} \bigr)+t^{q/\gamma}I\bigl(X_{j}>t^{q/\gamma}\bigr), \\& X_{j}^{(t,2)}=\bigl(X_{j}-t^{q/\gamma}\bigr)I \bigl(t^{q/\gamma}<X_{j}\le t^{q/\gamma }+t^{1/\gamma} \bigr)+t^{1/\gamma}I\bigl(X_{j}>t^{q/\gamma}+t^{1/\gamma} \bigr), \\& X_{j}^{(t,3)}=\bigl(X_{j}-t^{q/\gamma}-t^{1/\gamma} \bigr)I\bigl(X_{j}>t^{q/\gamma }+t^{1/\gamma}\bigr), \\& X_{j}^{(t,4)}=\bigl(X_{j}+t^{q/\gamma}\bigr)I \bigl(-t^{q/\gamma}-t^{1\gamma}\le X_{j}<-t^{q/\gamma} \bigr)-t^{1/\gamma}I\bigl(X_{j}<-t^{q/\gamma}-t^{1\gamma} \bigr), \\& X_{j}^{(t,5)}=\bigl(X_{j}+t^{q/\gamma}+t^{1/\gamma} \bigr)I\bigl(X_{j}<-t^{q/\gamma }-t^{1/\gamma}\bigr), \end{aligned}$$
then
\(X_{j}=\sum_{l=1}^{5} X_{j}^{(t, l)}\). Note that
$$\begin{aligned}& \sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2 } \int_{n^{\gamma \alpha}}^{\infty}P \Bigl(\max_{1\le k\le n}|S_{k}|>t^{1/\gamma} \Bigr)\,dt \\& \quad\le \sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2 }\int _{n^{\gamma\alpha }}^{\infty}P \Biggl(\max_{1\le k\le n} \Biggl\vert \sum_{j=1}^{k}X_{j}^{(t,1)} \Biggr\vert >t^{1/\gamma}/5 \Biggr)\,dt \\& \quad\quad{} +\sum_{l=2}^{3} \sum _{n=1}^{\infty}n^{\alpha( p-\gamma)-2 }\int_{n^{\gamma\alpha}}^{\infty}P \Biggl( \sum_{j=1}^{n}X_{j}^{(t,l)}>t^{1/\gamma}/5 \Biggr)\,dt \\& \quad\quad{} +\sum_{l=4}^{5} \sum _{n=1}^{\infty}n^{\alpha( p-\gamma)-2 }\int_{n^{\gamma\alpha}}^{\infty}P \Biggl(-\sum_{j=1}^{n}X_{j}^{(t,l)}>t^{1/\gamma}/5 \Biggr)\,dt \\& \quad\stackrel{\mathrm{def}}{=} \sum_{l=1}^{5} I_{l}. \end{aligned}$$
Therefore to prove (
2.2), it suffices to show that
\(I_{l}<\infty\) for
\(l=1, 2, 3, 4, 5\).
For
\(I_{1}\), we first prove that
$$ \sup_{t\ge n^{\gamma\alpha}}t^{-1/\gamma}\max_{1\le k\le n}\Biggl\vert E\sum_{j=1}^{k}X_{j}^{(t,1)} \Biggr\vert \to0,\quad n\to\infty. $$
(2.7)
When
\(\alpha\le1\). Since
\(\alpha p>1\) implies
\(p>1\), by Lemma
1.4 and
\(EX_{j}=0\),
\(j\ge1\), we have
$$\begin{aligned}& \sup_{t\ge n^{\gamma\alpha}}t^{-1/\gamma}\max_{1\le k\le n} \Biggl\vert E\sum_{j=1}^{k}X_{j}^{(t,1)} \Biggr\vert \\& \quad\le\sup_{t\ge n^{\gamma\alpha}}t^{-1/\gamma}\sum _{j=1}^{n}E \bigl\{ |X_{j}|I \bigl(|X_{j}|>t^{q/\gamma}\bigr)+t^{q/\gamma}I \bigl(|X_{j}|>t^{q/\gamma}\bigr) \bigr\} \\& \quad\le2\sup_{t\ge n^{\gamma\alpha}}t^{-1/\gamma}\sum _{j=1}^{n}E|X_{j}|I\bigl(|X_{j}|>t^{q/\gamma} \bigr) \\& \quad\le Cn\sup_{t\ge n^{\gamma\alpha}}t^{-1/\gamma}E|X|I\bigl(|X|> t^{q/\gamma}\bigr) \\& \quad\le Cn^{1-\alpha}E|X| I\bigl(|X|> n^{\alpha q}\bigr) \\& \quad \le Cn^{1-\alpha p q -\alpha(1-q)}E|X|^{p}\to0,\quad n\to\infty. \end{aligned}$$
When
\(\alpha>1\) and
\(p\ge1\).
$$\begin{aligned}& \sup_{t\ge n^{\gamma\alpha}}t^{-1/\gamma}\max_{1\le k\le n} \Biggl\vert E\sum_{j=1}^{k}X_{j}^{(t,1)} \Biggr\vert \\& \quad\le \sup_{t\ge n^{\gamma\alpha}}t^{-1/\gamma}\sum _{j=1}^{n} E|X_{j}| \le Cn \sup _{t\ge n^{\gamma\alpha}}t^{-1/\gamma}E|X| \le Cn^{1-\alpha }\to0,\quad n\to \infty. \end{aligned}$$
When
\(\alpha>1\) and
\(p< 1\),
$$\begin{aligned}& \sup_{t\ge n^{\gamma\alpha}}t^{-1/\gamma}\max_{1\le k\le n} \Biggl\vert E\sum_{j=1}^{k}X_{j}^{(t,1)} \Biggr\vert \\& \quad\le \sup_{t\ge n^{\gamma\alpha}}t^{-1/\gamma}\sum _{j=1}^{n}E \bigl\{ |X_{j}|I \bigl(|X_{j}|\le t^{q/\gamma}\bigr)+t^{q/\gamma}I \bigl(|X_{j}|>t^{q/\gamma}\bigr) \bigr\} \\& \quad\le \sup_{t\ge n^{\gamma\alpha}}t^{-1/\gamma}\sum _{j=1}^{n} t^{q(1-p)/\gamma} E|X_{j}|^{p} \le Cn \sup_{t\ge n^{\gamma\alpha}}t^{\{ q(1-p)-1\}/\gamma} E|X|^{p} \\& \quad\le Cn ^{1-\alpha p q-(1-q)\alpha}\to0,\quad n\to\infty. \end{aligned}$$
Therefore (
2.7) holds. By (
2.7), in order to prove
\(I_{1}<\infty\), it is enough to show that
$$I_{1}^{*}:=\sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2 }\int_{n^{\gamma\alpha }}^{\infty}P \Biggl(\max _{1\le k\le n}\Biggl\vert \sum_{j=1}^{k} \bigl(X_{j}^{(t,1)}-EX_{j}^{(t,1)} \bigr)\Biggr\vert >t^{1/\gamma}/10 \Biggr)\,dt< \infty. $$
Fix any
\(v\ge2\) and
\(v>\max\{p/(1-q), \gamma/(1-q), 2\gamma /[2-(2-p)q], 2(\alpha p-1)/[2\alpha(1-q)+(\alpha p q-1)], (\alpha p-1)/(\alpha-1/2)\}\), by Markov’s inequality, Lemma
1.1, Lemma
1.3, and
\(C_{r}\)-inequality, we have
$$\begin{aligned} I_{1}^{*} \le& C\sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2 } \\ &{}\times\int_{n^{\gamma\alpha}}^{\infty}t^{-v/\gamma} \bigl(\log(4n)\bigr)^{v} \Biggl\{ \sum_{j=1}^{n}E \bigl\vert X_{j}^{(t,1)}\bigr\vert ^{v}+ \Biggl( \sum_{j=1}^{n}E \bigl(X_{j}^{(t,1)} \bigr)^{2} \Biggr)^{v/2} \Biggr\} \,dt \\ \le & C\sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2 } \bigl(\log(4n)\bigr)^{v}\\ &{}\times\int_{n^{\gamma\alpha}}^{\infty}t^{-v/\gamma} \sum_{j=1}^{n} \bigl\{ E|X_{j}|^{v}I\bigl(|X_{j}|\le t^{\frac{q}{\gamma}} \bigr)+t^{qv/\gamma} P\bigl(|X_{j}|>t^{\frac {q}{\gamma}}\bigr) \bigr\} \,dt \\ &{} + C\sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2 }\bigl( \log(4n)\bigr)^{v} \\ &{}\times\int_{n^{\gamma\alpha}}^{\infty}t^{\frac{-v}{\gamma}} \Biggl\{ \sum_{j=1}^{n} \bigl(EX_{j}^{2}I\bigl(|X_{j}|\le t^{\frac{q}{\gamma}} \bigr)+t^{\frac {2q}{\gamma}} P\bigl(|X_{j}|>t^{\frac{q}{\gamma}}\bigr) \bigr) \Biggr\} ^{\frac {v}{2}}\,dt \\ \stackrel{\mathrm{def}}{=} &I_{11}+I_{12}. \end{aligned}$$
Note that
$$\begin{aligned} I_{11} \le & C\sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-1 }\bigl(\log (4n)\bigr)^{v}\int_{n^{\gamma\alpha}}^{\infty}t^{-(1-q)v/\gamma} \,dt \\ \le & C\sum_{n=1}^{\infty}n^{\alpha p-\alpha(1-q)v-1 } \bigl(\log(4n)\bigr)^{v} < \infty. \end{aligned}$$
If
\(\max\{p,\gamma\}< 2\), by Lemma
1.4, we have
$$\begin{aligned} I_{12} \le & C\sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2 }\bigl(\log(4n)\bigr)^{v} \int_{n^{\gamma\alpha}}^{\infty}t^{\frac{-v}{\gamma}} \Biggl\{ t^{(2-p)q/\gamma}\sum_{j=1}^{n}E|X_{j}|^{p} \Biggr\} ^{\frac{v}{2}}\,dt \\ \le & C\sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2+v/2 } \bigl(\log(4n)\bigr)^{v} \int_{n^{\gamma\alpha}}^{\infty}t^{\frac{-[2-(2-p)q]v}{2\gamma}} \bigl(E|X|^{p} \bigr)^{\frac{v}{2}}\,dt \\ \le & C\sum_{n=1}^{\infty}n^{\alpha p-2-[\alpha(1-q)+(\alpha p q-1)/2]v } \bigl(\log(4n)\bigr)^{v} < \infty. \end{aligned}$$
If
\(\max\{p,\gamma\}\ge 2\), note that
\(E|X|^{2}<\infty\), by Lemma
1.4, we have
$$\begin{aligned} I_{12} \le & C\sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2+v/2 }\bigl(\log (4n)\bigr)^{v}\int_{n^{\gamma\alpha}}^{\infty}t^{-v/\gamma} \,dt \\ \le & C\sum_{n=1}^{\infty}n^{\alpha p-2-(\alpha-1/2)v } \bigl(\log (4n)\bigr)^{v}< \infty. \end{aligned}$$
Therefore,
\(I_{1}^{*}<\infty\), so
\(I_{1}<\infty\).
For
\(I_{2}\), we first prove
$$ \sup_{t\ge n^{\gamma\alpha}} \Biggl\{ t^{-1/\gamma}\sum _{j=1}^{n}EX_{j}^{(t,2)} \Biggr\} \to0,\quad n \to\infty. $$
(2.8)
When
\(p>1\), we have by Lemma
1.4 that
$$\begin{aligned}& \sup_{t\ge n^{\gamma\alpha}} \Biggl\{ t^{-1/\gamma}\sum _{j=1}^{n}EX_{j}^{(t,2)} \Biggr\} \\& \quad\le \sup_{t\ge n^{\gamma\alpha}}t^{-1/\gamma}\sum _{j=1}^{n} \bigl\{ EX_{j}I \bigl(X_{j}>t^{q/\gamma}\bigr)+t^{1/\gamma}P \bigl(X_{j}>t^{q/\gamma}+t^{1/\gamma }\bigr) \bigr\} \\& \quad\le \sup_{t\ge n^{\gamma\alpha}}t^{-1/\gamma}\sum _{j=1}^{n} \bigl\{ EX_{j}I \bigl(X_{j}>t^{q/\gamma}\bigr)+EX_{j}I \bigl(X_{j}>t^{q/\gamma}+t^{1/\gamma}\bigr) \bigr\} \\& \quad\le Cn\sup_{t\ge n^{\gamma\alpha}}t^{-1/\gamma }E|X|I\bigl(|X|>t^{q/\gamma} \bigr) \le Cn^{1-\alpha}E |X| I\bigl(|X|>n^{q\alpha}\bigr) \\& \quad\le Cn^{1-q \alpha p-\alpha(1-q)} E|X|^{p} \to0,\quad n\to\infty. \end{aligned}$$
When
\(0< p\le1\), we have by Lemma
1.4
$$\begin{aligned}& \sup_{t\ge n^{\gamma\alpha}} \Biggl\{ t^{-1/\gamma}\sum _{j=1}^{n}EX_{j}^{(t,2)} \Biggr\} \\& \quad\le \sup_{t\ge n^{\gamma\alpha}}t^{-1/\gamma}\sum _{j=1}^{n} \bigl\{ E|X_{j}|I \bigl(|X_{j}|\le2 t^{1/\gamma}\bigr)+t^{1/\gamma}P \bigl(|X_{j}|>2t^{q/\gamma }\bigr) \bigr\} \\& \quad\le Cn\sup_{t\ge n^{\gamma\alpha}}t^{-1/\gamma} \bigl\{ E|X|I\bigl(|X|\le 2 t^{1/\gamma}\bigr)+2 t^{1/\gamma} P\bigl(|X|> 2 t^{1/\gamma}\bigr)+ t^{1/\gamma }P\bigl(|X|>2t^{q/\gamma}\bigr) \bigr\} \\& \quad\le Cn\sup_{t\ge n^{\gamma\alpha}} \bigl\{ t^{-p/\gamma }E|X|^{p}+t^{-pq/\gamma} E|X|^{p} \bigr\} \\& \quad\le Cn^{1-\alpha p q} \to0,\quad n\to\infty. \end{aligned}$$
Therefore (
2.8) holds. By (
2.8), in order to prove
\(I_{2}<\infty\), it is enough to show that
$$I_{2}^{*} := \sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2 }\int_{n^{\gamma \alpha}}^{\infty}P \Biggl( \sum _{j=1}^{n} \bigl(X_{j}^{(t,2)}-EX_{j}^{(t,2)} \bigr)>t^{1/\gamma}/10 \Biggr)\,dt < \infty. $$
Fix any
\(v\ge2\) (to be specified later), by Markov’s inequality, Lemma
1.1, Lemma
1.2,
\(C_{r}\)-inequality, Jensen’s inequality, and Lemma
1.4, we have
$$\begin{aligned} I_{2}^{*} \le & C\sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2 }\int_{n^{\gamma\alpha}}^{\infty}t^{-v/\gamma} \Biggl\{ \sum_{j=1}^{n}E\bigl\vert X_{j}^{(t,2)}\bigr\vert ^{v}+ \Biggl(\sum _{j=1}^{n}E \bigl(X_{j}^{(t,2)} \bigr)^{2} \Biggr)^{v/2}\,dt \Biggr\} \\ \le & C\sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2 }\int _{n^{\gamma \alpha}}^{\infty}t^{-v/\gamma} \sum _{j=1}^{n} \bigl\{ E|X_{j}|^{v}I \bigl(|X_{j}|\le 2t^{1/\gamma}\bigr)+t^{v/\gamma} P \bigl(X_{j}>t^{1/\gamma}\bigr) \bigr\} \,dt \\ &{} + C\sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2 }\int _{n^{\gamma\alpha }}^{\infty}t^{-v/\gamma} \Biggl\{ \sum _{j=1}^{n}E \bigl(X_{j}^{2}I \bigl(|X_{j}|\le 2t^{1/\gamma}\bigr)+t^{2/\gamma} P \bigl(X_{j}>t^{1/\gamma}\bigr) \bigr) \Biggr\} ^{v/2}\,dt \\ \le & C\sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-1 }\int _{n^{\gamma \alpha}}^{\infty}t^{-v/\gamma} E|X|^{v}I \bigl(|X|\le2t^{1/\gamma}\bigr)\,dt \\ &{} +C\sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-1 }\int _{n^{\gamma\alpha }}^{\infty}P\bigl(|X|>t^{1/\gamma}\bigr)\,dt \\ &{} + C\sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2+v/2 }\int _{n^{\gamma \alpha}}^{\infty}t^{-v/\gamma} \bigl\{ E|X|^{2}I\bigl(|X|\le2t^{1/\gamma }\bigr) \bigr\} ^{v/2}\,dt \\ &{} +C\sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2+v/2 }\int _{n^{\gamma \alpha}}^{\infty}\bigl( P\bigl(|X|>t^{1/\gamma}\bigr) \bigr)^{v/2}\,dt \\ \stackrel{\mathrm{def}}{=} &I_{21}+I_{22}+I_{23}+I_{24}. \end{aligned}$$
We get by the mean-value theorem and a standard computation
$$\begin{aligned} I_{22} = & C\sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-1 }\sum_{j=n}^{\infty}\int _{j^{\gamma\alpha}}^{(j+1)^{\gamma\alpha}} P\bigl(|X|>t^{1/\gamma}\bigr)\,dt \\ \le & C\sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-1 }\sum _{j=n}^{\infty}j^{\gamma\alpha-1} P \bigl(|X|>j^{\alpha}\bigr) \\ = & C\sum_{j=1}^{\infty}j^{\gamma\alpha-1} P \bigl(|X|>j^{\alpha}\bigr) \sum_{n=1}^{j} n^{\alpha( p-\gamma)-1 } \\ \le & \begin{cases} C\sum_{j=1}^{\infty}j^{\alpha p -1} P(|X|>j^{\alpha}), & \gamma< p,\\ C\sum_{j=1}^{\infty}j^{\alpha p-1} \log j P(|X|>j^{\alpha}) , & \gamma =p,\\ \sum_{j=1}^{\infty}j^{\gamma\alpha-1} P(|X|>j^{\alpha}) , & \gamma>p \end{cases} \\ \le & \begin{cases} CE|X|^{p}, & \gamma<p,\\ CE|X|^{p}\log(1+|X|) , & \gamma=p,\\ CE|X|^{\gamma},& \gamma>p \end{cases} \\ < & \infty. \end{aligned}$$
When
\(\max\{p,\gamma\}< 2\), let
\(v=2\). We have
\(I_{24}=I_{22}<\infty\) and
$$\begin{aligned} I_{21} =& I_{23} = C\sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-1 }\sum_{j=n}^{\infty}\int _{j^{\gamma\alpha}}^{(j+1)^{\gamma\alpha}} t^{-2/\gamma} E|X|^{2}I \bigl(|X|\le2t^{1/\gamma}\bigr)\,dt \\ \le & C\sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-1 } \sum_{j=n}^{\infty}j^{(-2+\gamma)\alpha-1} E|X|^{2}I\bigl(|X|\le2(j+1)^{\alpha}\bigr) \\ = & C\sum_{j=1}^{\infty}j^{(-2+\gamma)\alpha-1} E|X|^{2}I\bigl(|X|\le 2(j+1)^{\alpha}\bigr) \sum _{n=1}^{j} n^{\alpha( p-\gamma)-1 } \\ \le & \begin{cases} C\sum_{j=1}^{\infty}j^{\alpha(p-2)-1} E|X|^{2}I(|X|\le2(j+1)^{\alpha}), & \gamma< p,\\ C\sum_{j=1}^{\infty}j^{\alpha(p-2)-1} \log j E|X|^{2}I(|X|\le 2(j+1)^{\alpha}) , & \gamma=p,\\ C\sum_{j=1}^{\infty}j^{\alpha(\gamma-2) -1} E|X|^{2}I(|X|\le 2(j+1)^{\alpha}) , & \gamma>p \end{cases} \\ \le & \begin{cases} CE|X|^{p}, & \gamma<p,\\ CE|X|^{p}\log(1+|X|) , & \gamma=p,\\ CE|X|^{\gamma},& \gamma>p \end{cases} \\ < & \infty. \end{aligned}$$
(2.9)
When
\(\max\{p,\gamma\}\ge 2\), let
\(v>\max\{\gamma, (\alpha p -1)/(\alpha-1/2)\}\). Note that
\(E|X|^{2}<\infty\)
$$I_{23} \le C\sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2+v/2 }\int_{n^{\gamma\alpha}}^{\infty}t^{-v/\gamma}\, dt = C\sum_{n=1}^{\infty}n^{\alpha p-2-(\alpha-1/2)v}< \infty, $$
and by the Markov inequality, we have
$$I_{24} \le C\sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2+v/2 }\int_{n^{\gamma\alpha}}^{\infty}t^{-v/\gamma} \,dt< \infty. $$
The proof of
\(I_{21}<\infty\) is similar to that (
2.9), so it is omitted. Therefore,
\(I_{2}^{*}<\infty\), so
\(I_{2}<\infty\).
For
\(I_{3}\), we get
$$\begin{aligned} I_{3} \le& \sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2 }\int_{n^{\gamma \alpha}}^{\infty}P \Biggl\{ \bigcup_{j=1}^{n}\bigl(X_{j}^{(t,3)}>0\bigr) \Biggr\} \,dt \\ = & \sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-2 }\int _{n^{\gamma\alpha }}^{\infty}\sum_{j=1}^{n} P \bigl( X_{j}>t^{1/\gamma}+t^{q/\gamma} \bigr)\,dt \\ \le & C \sum_{n=1}^{\infty}n^{\alpha( p-\gamma)-1 } \int_{n^{\gamma \alpha}}^{\infty}P\bigl(|X|>t^{1/\gamma}\bigr)\,dt =CI_{22}< \infty. \end{aligned}$$
By similar proofs to
\(I_{2}<\infty\) and
\(I_{3}<\infty\), we have
\(I_{4}<\infty \) and
\(I_{5}<\infty\), respectively. Therefore, (
2.2) holds.