We first assume that
\(\xi \) is smooth. Via the inverse Fourier transform, the walk
U corresponds to an
\((n \times n)\)-matrix
\(\widehat{U}\) whose entries are analytic functions on
\(\mathbb {T}_{2 \pi }^d\). The initial unit vector
\(\xi \) corresponds to a smooth element
\(\widehat{\xi } \in L^2 \left( \mathbb {T}_{2 \pi }^d \right) \otimes \mathbb {C}^n\). For every
\(i = 1, \cdots , d\), the self-adjoint operator
\({\widehat{D}}_i\) is given by
\(- \mathbf {i}\frac{\partial }{ \partial k_i}\). Define
\({\widehat{D}}\) by
\(- \mathbf {i}\sum _i w_i \frac{\partial }{\partial k_i}\). By Eq. (
7) in Lemma
3.7, the mean of the function
\(\exp (\mathbf {i}(\cdot , \mathbf {w})_{\mathbb {R}^d})\) on
\(\mathbb {R}^d\) with respect to
\(p_t\) is equal to the following inner product:
$$\begin{aligned}&\int _{\mathbf {v}\in \mathbb {R}^d} \exp (\mathbf {i}(\mathbf {v}, \mathbf {w})_{\mathbb {R}^d})p_t(d \mathbf {v})\\&\quad = \left\langle \exp \left( \mathbf {i}t^{-1} \widehat{D} \right) \widehat{U}^t \widehat{\xi }, \widehat{U}^t \widehat{\xi } \right\rangle \\&\quad = \left\langle \widehat{U}^{-t} \exp \left( \mathbf {i}t^{-1} \widehat{D} \right) \widehat{U}^t \exp \left( -\mathbf {i}t^{-1} \widehat{D} \right) \exp \left( \mathbf {i}t^{-1} \widehat{D} \right) \widehat{\xi }, \widehat{\xi } \right\rangle . \end{aligned}$$
Let
\(\widehat{H}\) be the limit of the averages of logarithmic derivatives of
\(\widehat{U}^t\) with respect to the differential operator
\(- \mathbf {i}\sum w_i \frac{\partial }{\partial k_i}\). As in the proof of Proposition
4.2, define self-adjoint operators
\(\widehat{H_i}\) by
$$\begin{aligned} - \mathbf {i}\lim _{t \rightarrow \infty } \widehat{U}(\mathbf {k})^{-t} \frac{\partial \widehat{U}^t}{\partial k_i}(\mathbf {k}), \end{aligned}$$
and
\(\widehat{H}\) by
\(\sum _{i=1}^d w_i \widehat{H_i}\). By Proposition
4.2, the operator
$$\begin{aligned} \widehat{U}^{-t} \exp \left( \mathbf {i}t^{-1} \widehat{D} \right) \widehat{U}^t \exp \left( -\mathbf {i}t^{-1} \widehat{D} \right) \end{aligned}$$
converges to
\(\exp \left( \mathbf {i}\widehat{H} \right) \) in the strong operator topology. The vector
\(\exp \left( \mathbf {i}t^{-1} \widehat{D} \right) \widehat{\xi }\) is given by
\(\left[ \exp \left( \mathbf {i}t^{-1} \widehat{D} \right) \widehat{\xi } \right] (\mathbf {k}) = \widehat{\xi }(\mathbf {k}+ t^{-1} \mathbf {w})\). It is uniformly close to
\(\widehat{\xi }(\mathbf {k})\). As
t tends to infinity, the above integral converges to
$$\begin{aligned} \left\langle \exp \left( \mathbf {i}\widehat{H} \right) \widehat{\xi }, \widehat{\xi } \right\rangle _{L^2 \left( \mathbb {T}_{2 \pi }^d \right) \otimes \mathbb {C}^d} = \left\langle \prod _i \exp (\mathbf {i}w_i H_i) \xi , \xi \right\rangle . \end{aligned}$$
We obtain
$$\begin{aligned} \lim _{t \rightarrow \infty } \int _{\mathbf {v}\in \mathbb {R}^d} \exp (\mathbf {i}(\mathbf {v}, \mathbf {w})_{\mathbb {R}^d})p_t(d \mathbf {v})= & {} \left\langle \prod _i \exp (\mathbf {i}w_i H_i) \xi , \xi \right\rangle \\= & {} \left\langle \int _{\mathbf {v}\in \mathbb {R}^d} \exp (\mathbf {i}(\mathbf {v}, \mathbf {w})_{\mathbb {R}^d}) \mathcal {E}(d \mathbf {v}) \xi , \xi \right\rangle . \end{aligned}$$
We obtain that for every linear combination
g of
\(\{ \exp (\mathbf {i}(\cdot , \mathbf {w})_{\mathbb {R}^d}) \ |\ \mathbf {w}\in \mathbb {R}^d \}\),
$$\begin{aligned}\lim _{t \rightarrow \infty } \int _{\mathbf {v}\in \mathbb {R}^d} g(\mathbf {v}) p_t(d \mathbf {v}) = \left\langle \int _{\mathbf {v}\in \mathbb {R}^d} g(\mathbf {v}) \mathcal {E}(d \mathbf {v}) \xi , \xi \right\rangle .\end{aligned}$$
By Theorem
3.10, there exists a compact subset
K of
\(\mathbb {R}^d\) such that
$$\begin{aligned} \lim _{t \rightarrow \infty } p_t(K) = 1. \end{aligned}$$
The linear span
\(\mathrm {span}\{ \exp (\mathbf {i}(\cdot , \mathbf {w})_{\mathbb {R}^d}) \ |\ \mathbf {w}\in \mathbb {R}^d \}\) is the space of trigonometric functions. By the theorem of Stone–Weierstrass, the linear span is dense in
C(
K) with respect to the supremum norm. It follows that for every bounded continuous function
f on
\(\mathbb {R}^d\),
$$\begin{aligned} \lim _{t \rightarrow \infty } \int _{\mathbf {v}\in \mathbb {R}^d} f(\mathbf {v}) p_t(d \mathbf {v}) = \left\langle \int _{\mathbf {v}\in \mathbb {R}^d} f(\mathbf {v}) \mathcal {E}(d \mathbf {v}) \xi , \xi \right\rangle . \end{aligned}$$
In the special case that
\(\xi \) is smooth, we finish the proof.
Let
\(\widetilde{\xi }\) be an initial unit vector in
\(\ell _2(\mathbb {Z}^d) \otimes \mathbb {C}^n = \ell _2(\mathbb {Z}^d \rightarrow \mathbb {C}^n)\) which is not necessarily smooth. Let
\(\widetilde{p_t}\) be the sequence of probability measures defined by
\(U^t\) and
\(\widetilde{\xi }\). Let
\(\epsilon \) be an arbitrary positive number. Choose a smooth unit vector
\(\xi \in \ell _2(\mathbb {Z}^d \rightarrow \mathbb {C}^n)\) satisfying that
\(\left\| \xi - \widetilde{\xi } \right\| < \epsilon \). For every element
\(\eta \) of
\(\ell _2(\mathbb {Z}^d \rightarrow \mathbb {C}^n)\), define an
\(\ell _1\) function
\(|\eta |^2\) on
\(\mathbb {Z}^d\) by
$$\begin{aligned} \left| \eta \right| ^2(\mathbf {x}) = \left\| \eta (\mathbf {x}) \right\| _{\mathbb {C}^n}^2, \end{aligned}$$
By the inequality
\(\left\| U^t \xi - U^t \widetilde{\xi } \right\| < \epsilon \), we have
\(\left\| |U^t \xi |^2 - \left| U^t \widetilde{\xi } \right| ^2 \right\| _{\ell _1} < 2 \epsilon \). By Eq. (
7), for every bounded Borel function
f on
\(\mathbb {R}^d\), we have
$$\begin{aligned} \left| \int _{\mathbf {v}\in \mathbb {R}^d} f(\mathbf {v}) p_t(d \mathbf {v}) - \int _{\mathbf {v}\in \mathbb {R}^d} f(\mathbf {v}) \widetilde{p_t} (d \mathbf {v}) \right|\le & {} \sup _{\mathbf {v}\in \mathbb {R}^d} |f(\mathbf {v})| \cdot \left\| |U^t \xi |^2 - \left| U^t \widetilde{\xi } \right| ^2 \right\| _{\ell _1} \\\le & {} 2 \epsilon \sup _{\mathbf {v}\in \mathbb {R}^d} |f(\mathbf {v})|. \end{aligned}$$
We also obtain
$$\begin{aligned}&\left| \left\langle \int _{\mathbf {v}\in \mathbb {R}^d} f(\mathbf {v}) \mathcal {E}(d \mathbf {v}) \xi , \xi \right\rangle - \left\langle \int _{\mathbf {v}\in \mathbb {R}^d} f(\mathbf {v}) \mathcal {E}(d \mathbf {v}) \widetilde{\xi }, \widetilde{\xi } \right\rangle \right| \\&\quad \le 2 \left\| \int _{\mathbf {v}\in \mathbb {R}^d} f(\mathbf {v}) \mathcal {E}(d \mathbf {v}) \right\| \left\| \xi - \widetilde{\xi } \right\| \le 2 \epsilon \sup _{\mathbf {v}\in \mathbb {R}^d} |f(\mathbf {v})|. \end{aligned}$$
It follows that for every bounded continuous function
f on
\(\mathbb {R}^d\),
$$\begin{aligned} \lim _{t \rightarrow \infty } \int _{\mathbf {v}\in \mathbb {R}^d} f(\mathbf {v}) \widetilde{p_t}(d \mathbf {v}) = \left\langle \int _{\mathbf {v}\in \mathbb {R}^d} f(\mathbf {v}) \mathcal {E}(d \mathbf {v}) \widetilde{\xi }, \widetilde{\xi } \right\rangle = \int _{\mathbf {v}\in \mathbb {R}^d} f(\mathbf {v}) \left\langle \mathcal {E}(d \mathbf {v}) \widetilde{\xi }, \widetilde{\xi } \right\rangle . \end{aligned}$$
It follows that the sequence of probability measures
\(\left\{ \widetilde{p_t} \right\} \) weakly converges.
\(\square \)