On the quotient stability of a family of functional equations

https://doi.org/10.1016/j.na.2009.02.123Get rights and content

Abstract

We show some stability results for a family of functional equations that contains the exponential and the Goła̧b–Schinzel functional equations.

Introduction

Let R, Z and N stand, as usual, for the sets of reals, integers and positive integers, respectively; moreover, we write R0R{0}, D+E{d+e:dD,eE} and cD{cd:dD} for cR, D,ER.

In what follows λR0 and M:RR denotes a continuous function that is multiplicative (i.e., M(xy)=M(x)M(y) for x,yR) and M(R){0}. Several particular forms of the functional equation f(x+M(f(x))y)=λf(x)f(y) (with the unknown function f mapping, e.g., a real linear space into R) have already found nontrivial applications in meteorology and fluid mechanics, theories of near rings and quasialgebras, finding algebraic substructures, theory of algebraic objects, and description of associative operations; for suitable references see the monograph [1] and the survey paper [2]. Note that, in the particular case: λ=1 and M(x)=1 for xR, Eq. (1) becomes the well-known exponential equation f(x+y)=f(x)f(y) and, if λ=1 and M(x)=x for xR, (1) has the form f(x+f(x)y)=f(x)f(y), which is now called the Goła̧b–Schinzel functional equation. Some recent results concerning solutions of Eq. (3) and its generalizations can be found in [3], [4], [5], [6], [7].

The investigation of stability of functional equations started with a problem posed by S.M. Ulam and a solution of it given by Hyers [8]. Among other results, the superstability of the exponential equation (2) has been discovered and in connection with that phenomenon, a new approach has been suggested (see [9]) that is now called: stability in the sense of Ger (for more information on stability and superstability of functional equations we refer the reader to, e.g., [10], [11], [12], [13]; for some recent results on these subjects see, e.g., [14], [15], [16], [17], [18], [19], [20], [21], [22], [23], [24], [25], [26], [27], [37]). Motivated by this approach, Chudziak [28] (see also [29]) has proved that, in the class of functions f, mapping a linear space Y over a field K{R,C} into K, such that the set Af{xY;f(x)0} has an algebraically interior point, the functional equation f(x+f(x)ny)=λf(x)f(y) (with fixed nN) is superstable in the sense of Ger. Namely he has shown that every function f:YK such that the set Af possesses an algebraically interior point and |f(x+f(x)ny)λf(x)f(y)1|εwhenever f(x)f(y)0,|λf(x)f(y)f(x+f(x)ny)1|εwhenever f(x+f(x)ny)0, with some ε(0,1), is a solution of Eq. (4) or it is bounded. Some further results related to or concerning the stability of (3) or (4) can be found in [30], [31], [32], [33].

The result in [28] (and in [29]) does not remain valid if we replace inequalities (5), (6) by the following weaker condition |f(x+f(x)ny)λf(x)f(y)1|εand|λf(x)f(y)f(x+f(x)ny)1|εwhenever f(x+f(x)ny)f(x)f(y)0. For instance, for λ=1, the function f:RR, given by the formulas f(x)=x+1n for x>0 and f(x)=0 for x0, satisfies (7) (with ε=0 and λ=1), but it is not a solution of (4) (take x>0 and y=0). However, it is easy to check that f satisfies (with λ=1) the functional equation f(x+f(x)ny)f(x)f(y)[f(x+f(x)ny)λf(x)f(y)]=0. In this paper we complete (and generalize to some extent) the results in [29], [28] by showing that every continuous solution f:RR of (7) satisfies Eq. (8) and, moreover, in the case where f(x0+f(x0)ny0)f(x0)f(y0)0 for some x0,y0R, it must be a solution of (4). We also extend these results to the case of Eq. (1); in particular, we prove analogous results for the exponential equation (2). In view of Remark 3, for M(R){1}, we should not expect to obtain such results under assumptions weaker than continuity of f (at each point of the domain); in the case M(R)={1} the situation is somewhat different, as it is shown in Proposition 1 and Corollary 1, Corollary 2.

The present paper gives a starting point for investigations of analogous problems in more general classes of functions, e.g., mapping a linear topological space Y over a field K{R,C} into K. However, since some additional longer arguments are necessary in such a case, they will be studied in next publications.

At the end of the paper (see Proposition 3) we show that a description of the continuous solutions f:RR of the equation f(x+M(f(x))y)f(x)f(y)[f(x+M(f(x))y)λf(x)f(y)]=0 can be easily derived from our main theorem (Theorem 2). In this way we generalize the main results in [34], where the continuous solutions f:RR of the functional equation f(x+f(x)y)f(x)f(y)[f(x+f(x)y)f(x)f(y)]=0 have been determined.

Section snippets

The case M(x)x and λ=1

In what follows μ1 is a fixed real number, f:RR denotes a continuous solution of the inequality 1μ|f(x+f(x)y)f(x)f(y)|μfor x,yR,f(x+f(x)y)f(x)f(y)0,A{xR:f(x)0}, BRA, τx(y)x+f(x)y for x,yR, and F(x,y)f(x+f(x)y)f(x)f(y)for x,yR,f(x)f(y)0. Moreover, we assume that f(x0+f(x0)y0)f(x0)f(y0)0 for some x0,y0R.

Lemma 1

The following three statements are valid.

  • (i)

    A{(,b),(a,),(,b)(a,),R} for some a,bR0 , ba .

  • (ii)

    The function f¯:RR , given by: f¯(x)=f(x) for xR , is a solution of(11).

  • (iii)

    If A=(a,

The case M(x)1 and λ=1

In this part X denotes a real linear space. We start with a result which follows from [35, Theorem 1] and will be useful in what follows.

Lemma 3

Let δ>0 , DX , D , h:DR , and|h(x+y)h(x)h(y)|δfor x,yD,x+yD.Suppose that 2DD or D2D . Then there is a unique h0:DR withh0(x+y)=h0(x)+h0(y)for x,yD,x+yD,|h(x)h0(x)|δfor xD.

Now we are in a position to prove the following.

Proposition 1

Let c1,c2[1,) , f:XR , S{xX:f(x)0} ,1c1|f(x+y)f(x)f(y)|c2for x,yX,f(x)f(y)f(x+y)0,S2Sor2SS.Then there exists a

The general case

Let us begin with the following remark.

Remark 1

Note that there is a0 such that M(x)=xa for x0 and either M(z)=M(z) for z<0 or M(z)=M(z) for z<0, because M is continuous and multiplicative (cf. [1]).

Now we are in a position to prove the main result.

Theorem 2

Let ε1,ε2[0,) , g:RR be continuous, and1ε1+1|g(x+M(g(x))y)λg(x)g(y)|ε2+1for x,yR,g(x+M(g(x))y)g(x)g(y)0.Then g is a solution of the functional equationg(x+M(g(x))y)g(x)g(y)=0or the following three conditions are valid.

  • (a)

    If M is odd, then|λg(x)|[1ε2+

Solutions of (1), (9) and (25)

We end the paper with three propositions that describe continuous solutions g:RR of functional equations (1), (9), (25).

Proposition 2

Let M(R){1} , λR{0} and g:RR be continuous. Then g is a solution of functional equation(1)if and only if one of the following five conditions holds.

  • (α)

    g(x)=1λ for xR .

  • (β)

    g(x)=0 for xR .

  • (γ)

    λ=1 , M is odd and there is cR0 such that either g(x)=M1(cx+1) for xR or g(x)=M1(max{cx+1,0}) for xR .

  • (δ)

    |λ|=1 , M is even, M(R){1} , and there is cR0 with g(x)=λM01(max{cx+1,0}) for xR ,

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