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A construction for a regular heptagon

Published online by Cambridge University Press:  22 September 2016

Crockett Johnson
Crockett Johnson*
Affiliation:
24 Owenoke, Westport, Connecticut 06880, USA
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Extract

Call the ends of a ruler A and Z, and (towards A) place on it a mark X. Draw a line BC the length of AX, and a square BCDE. Erect a perpendicular bisector of BC. With centre C and radius CE draw a circle. Now place the ruler (Fig. 1) so that AZ passes through B, with A on the perpendicular bisector of BC, and with X on the circle. Then ∠BAC = π/7.

Type
Research Article
Information
The Mathematical Gazette , Volume 59 , Issue 407 , March 1975 , pp. 17 - 21
Copyright
Copyright © Mathematical Association 1975

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