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2017 | OriginalPaper | Buchkapitel

Love Affairs Dynamics with One Delay in Losing Memory or Gaining Affection

verfasst von : Akio Matsumoto

Erschienen in: Optimization and Dynamics with Their Applications

Verlag: Springer Singapore

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Abstract

A dynamic model of a love affair between two people is examined under different conditions. First the two-dimensional model is analyzed without time delays in the interaction of the lovers. Conditions are derived for the existence of a unique as well as for multiple steady states. The nonzero steady states are always stable and the stability of the zero steady state depends on model parameters. Then a delay is assumed in the mutual-reaction process called the Gaining-affection process. Similarly to the no-delay case, the nonzero steady states are always stable. The zero steady state is either always stable or always unstable or it is stable for small delays and at a certain threshold stability is lost in which case the steady state bifurcates to a limit cycle. When delay is introduced to the self-reaction process called the Losing-memory process, then the asymptotic behavior of the steady state becomes more complex. The stability of the nonzero steady state is lost at a certain value of the delay and bifurcates to a limit cycle, while the stability of the zero steady state depends on model parameters and there is the possibility of multiple stability switches with stability losses and regains. All stability conditions and stability switches are derived analytically, which are also verified and illustrated by using computer simulation.

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Fußnoten
1
See Strogatz (1994) for more precise specification.
 
2
By definition,
$$\begin{aligned} \tanh (x)=\frac{e^{x}-e^{-x}}{e^{x}+e^{-x}} \end{aligned}$$
and its derivative is
$$\begin{aligned} \frac{d}{dx}\tanh (x)=\left( \frac{2}{e^{x}+e^{-x}}\right) ^{2}\le 1. \end{aligned}$$
It is clear that equality holds if \(x=0.\ \)If \(e^{x}=a\) for \(x\ne 0\), then
$$\begin{aligned} e^{x}+e^{-x}=a+\frac{1}{a}>2 \end{aligned}$$
implying
$$\begin{aligned} \frac{2}{e^{x}+e^{-x}}<1 \end{aligned}$$
Hence the strict inequality holds if \(x\ne 0\).
 
3
Liao and Ran (2007) further assume that Romeo also reacts to the delayed Juliet feeling \(y(t-\tau _{y})\) with \(\tau _{x}\ne \tau _{y}.\ \) Son and Park (2011) consider the special case where both individuals have the same delay\(\ \tau _{x}=\tau _{y}\) in the gaining-affection processes. The dynamic results obtained in those studies are essentially the same as the one to be obtained in the following one delay model.
 
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Metadaten
Titel
Love Affairs Dynamics with One Delay in Losing Memory or Gaining Affection
verfasst von
Akio Matsumoto
Copyright-Jahr
2017
Verlag
Springer Singapore
DOI
https://doi.org/10.1007/978-981-10-4214-0_9