Fix
\(t\geq 0\) and
\(f\in W_{\nu }^{1,p}\). In Lemma
4.6, we have already proved that
\(F(t,f)\in L^{p}_{\nu }\) under conditions (
4.17) and (
4.18). Let us show that
\(DF(t,f)\in L ^{p}_{\nu }\). By the chain rule, we have
$$\begin{aligned} DF(t,f)(x) &=\bigg\langle Dg\big(t,x,f(x)\big),\int _{0}^{x}g\big(t,y,f(y) \big)\,dy\bigg\rangle _{H} \\ & \phantom{=:}+\big\langle g\big(t,x,f(x)\big), g\big(t,x,f(x)\big) \big\rangle _{H}. \end{aligned}$$
Since the functions
\(g(t,x,f(x))\),
\(Dg(t,x,f(x))\) and
\(h(x):=\int _{0} ^{x}g(t,y,f(y))\) are measurable,
\(DF(t,f)\) is measurable. Moreover, by the Cauchy–Schwarz inequality, we obtain for each
\(x\in [0,\infty )\) that
$$\begin{aligned} |DF(t,f)(x)| &\leq \big\| Dg\big(t,x,f(x)\big)\big\| _{H}\int _{0}^{ \infty }\big\| g\big(t,x,f(x)\big)\big\| _{H}dx \\ & \phantom{=:}+\big\| g\big(t,x,f(x)\big)\big\| _{H}\big\| g\big(t,x,f(x) \big)\big\| _{H}. \end{aligned}$$
Using (
4.17) and Lemma
4.1, we obtain
$$\begin{aligned} |DF(t,f)(x)|\leq \|\bar{g}\|_{1}\big\| Dg\big(t,x,f(x)\big)\big\| _{H}+|\bar{g}(x)|^{2}, \qquad x\in [0,\infty ). \end{aligned}$$
Note that
$$\begin{aligned} Dg\big(t,x,f(x)\big)=D_{x}g\big(t,x,f(x)\big)+D_{u}g\big(t,x,f(x) \big)\,Df(x), \qquad x\in [0,\infty ). \end{aligned}$$
Therefore, by (
4.19) and (
4.21), we get for each
\(x\in [0,\infty )\) that
$$\begin{aligned} \big\| Dg\big(t,x,f(x)\big)\big\| _{H} &\leq \big\| D_{x}g\big(t,x,f(x) \big)\big\| _{H}+\big\| D_{u}g\big(t,x,f(x)\big)\big\| _{H}|Df(x)| \\ &\leq |D\bar{g}(x)t|+K_{1}|Df(x)|. \end{aligned}$$
(4.24)
Taking into account the last inequality, we obtain
$$\begin{aligned} |DF(t,f)(x)|\leq \|\bar{g}\|_{1}|D\bar{g}(x)|+K_{1}\|\bar{g}\|_{1}|Df(x)|+| \bar{g}(x)|^{2}, \qquad x\in [0,\infty ). \end{aligned}$$
Thus, by the last inequality and Proposition
4.11, we infer that
$$ \int _{0}^{\infty }|DF(t,f)|^{p}e^{\nu x}dx\leq 3^{p}\|\bar{g}\|^{p} _{1}\|D\bar{g}\|^{p}_{\nu ,p}+3^{p}K^{p}_{1}\|\bar{g}\|^{p}_{1}\|Df\| ^{p}_{\nu ,p}+3^{p}\|\bar{g}\|^{p}_{\infty }\|\bar{g}\|^{p}_{\nu ,p}. $$
Therefore
\(DF(t,f)\in L^{P}_{\nu }\) and hence
\(F\) is well defined. Moreover, it follows from (
4.10) and the last inequality that
$$\begin{aligned} \|F(t,f)\|_{W_{\nu }^{1,p}} &\leq \|\bar{g}\|_{1}\|\bar{g}\|_{\nu ,p}+3 \|\bar{g}\|_{1}\|D\bar{g}\|_{\nu ,p} \\ & \phantom{=:}+3K_{1}\|\bar{g}\|_{1}\|Df\|_{\nu ,p}+3\|\bar{g}\|_{ \infty }\|\bar{g}\|_{\nu ,p}, \end{aligned}$$
which gives the desired conclusion (
4.23).
Let us now prove that
\(F\) is locally Lipschitz on balls. Fix
\(t\geq 0\) and
\(f_{1},f_{2}\in W^{1,p}_{\nu }\). Note that
$$\begin{aligned} &F(t,f_{1})(x)-F(t,f_{2})(x) \\ &=\bigg\langle g\big(t,x,f_{1}(x)\big)-g\big(t,x,f_{2}(x)\big),\int _{0}^{x}g\big(t,y,f_{2}(y)\big)\,dy\bigg\rangle _{H} \\ & \phantom{=:}+\bigg\langle g\big(t,x,f_{1}(x)\big),\int _{0}^{x}\Big(g \big(t,y,f_{1}(y)\big)-g\big(t,y,f_{2}(y)\big)\Big)dy\bigg\rangle _{H}, \qquad x\in [0,\infty ). \end{aligned}$$
By the Cauchy–Schwarz inequality, we have
$$\begin{aligned} &|F(t,f_{1})(x)-F(t,f_{2})(x)| \\ &\leq \big\| g\big(t,x,f_{1}(x)\big)-g\big(t,x,f_{2}(x)\big)\big\| _{H}\int _{0}^{\infty }\big\| g\big(t,x,f_{2}(x)\big)\big\| _{H}dx \\ & \phantom{=:}+\big\| g\big(t,x,f_{1}(x)\big)\big\| _{H}\int _{0}^{ \infty }\big\| g\big(t,x,f_{1}(x)\big)-g\big(t,x,f_{2}(x)\big)\big\| dx, \qquad x\in [0,\infty ). \end{aligned}$$
Using (
4.17) and (
4.18), we obtain for each
\(x\in [0,\infty )\) that
$$\begin{aligned} |F(t,f_{1})(x)-F(t,f_{2})(x)| &\leq |\hat{g}(x)|\,|f_{1}(x)-f_{2}(x)| \int _{0}^{\infty }|\bar{g}(x)|dx \\ & \phantom{=:}+|\bar{g}(x)|\int _{0}^{\infty }|\hat{g}(x)|\,|f_{1}(x)-f _{2}(x)|dx. \end{aligned}$$
It follows from Lemma
4.1 and Proposition
4.11 that
$$\begin{aligned} |F(t,f_{1})(x)-F(t,f_{2})(x)| &\leq \|\bar{g}\|_{1}|\hat{g}(x)||f_{1}(x)-f _{2}(x)| \\ & \phantom{=:}+\|f_{1}-f_{2}\|_{1}\|\hat{g}\|_{\infty }|\bar{g}(x)|, \qquad x\in [0,\infty ). \end{aligned}$$
Taking into account the last inequality and Proposition
4.11, we infer that
$$\begin{aligned} \|F(t,f_{1})-F(t,f_{2})\|_{\nu ,p} &\leq 2\|\bar{g}\|_{1}\|\hat{g}\| _{\infty }\|f_{1}-f_{2}\|_{\nu ,p} \\ & \phantom{=:}+2\|\hat{g}\|_{\infty }\|\bar{g}\|_{\nu ,p}\|f_{1}-f_{2} \|_{1}. \end{aligned}$$
(4.25)
By the chain rule, we get for
\(x\in [0,\infty )\) that
$$\begin{aligned} D\big(F(t,f_{1})(x)-F(t,f_{2})(x)\big) &=\bigg\langle Dg\big(t,x,f _{1}(x)\big),\int _{0}^{x}g\big(t,y,f_{1}(y)\big)\,dy\bigg\rangle _{H} \\ & \phantom{=:}+\big\langle g\big(t,x,f_{1}(x)\big),g\big(t,x,f_{1}(x) \big)\big\rangle _{H} \\ & \phantom{=:}-\bigg\langle Dg\big(t,x,f_{2}(x)\big),\int _{0}^{x}g \big(t,y,f_{2}(y)\big)\,dy\bigg\rangle _{H} \\ & \phantom{=:}-\big\langle g\big(t,x,f_{2}(x)\big),g\big(t,x,f_{2}(x) \big)\big\rangle _{H}. \end{aligned}$$
Note that
$$\begin{aligned} &D\big(F(t,f_{1})(x)-F(t,f_{2})(x)\big) \\ &=\bigg\langle Dg\big(t,x,f_{1}(x)\big),\int _{0}^{x}\Big(g\big(t,y,f _{1}(y)\big)-g\big(t,y,f_{2}(y)\big)\Big)\,dy\bigg\rangle _{H} \\ & \phantom{=:}+\bigg\langle Dg\big(t,x,f_{1}(x)\big)-Dg\big(t,x,f_{2}(x) \big),\int _{0}^{x}g\big(t,y,f_{2}(y)\big)\,dx\bigg\rangle _{H} \\ & \phantom{=:}+\big\langle g\big(t,x,f_{1}(x)\big),g\big(t,x,f_{1}(x) \big)-g\big(t,x,f_{2}(x)\big)\big\rangle _{H} \\ & \phantom{=:}+\big\langle g\big(t,x,f_{1}(x)\big)-g\big(t,x,f_{2}(x) \big),g\big(t,x,f_{2}(x)\big)\big\rangle _{H}, \qquad x\in [0,\infty ). \end{aligned}$$
Using the Cauchy–Schwarz inequality and (
4.17) and (
4.18), we obtain
$$\begin{aligned} &\big|D\big(F(t,f_{1})(x)-F(t,f_{2})(x)\big)\big| \\ &\leq \big\| Dg\big(t,x,f_{1}(x)\big)\big\| _{H}\int _{0}^{\infty }| \hat{g}(x)|\,|f_{1}(x)-f_{2}(x)|dx \\ & \phantom{=:}+\big\| Dg\big(t,x,f_{1}(x)\big)-Dg\big(t,x,f_{2}(x) \big)\big\| _{H}\int _{0}^{\infty }|\bar{g}(x)|\,dx \\ & \phantom{=:}+2|\bar{g}(x)|\,|\hat{g}(x)|\,|f_{1}(x)-f_{2}(x)|, \qquad x\in [0,\infty ). \end{aligned}$$
By Lemma
4.1 and Proposition
4.11, we get for
\(x\in [0,\infty )\) that
$$\begin{aligned} \big|D\big(F(t,f_{1})(x)-F(t,f_{2})(x)\big)\big| &\leq \|\hat{g}\| _{\infty }\|f_{1}-f_{2}\|_{1}\big\| Dg\big(t,x,f_{1}(x)\big)\big\| _{H} \\ & \phantom{=:}+\|\bar{g}\|_{1}\big\| Dg\big(t,x,f_{1}(x)\big)-Dg\big(t,x,f _{2}(x)\big)\big\| _{H} \\ & \phantom{=:}+2|\bar{g}(x)||\hat{g}(x)||f_{1}(x)-f_{2}(x). \end{aligned}$$
Note that
$$\begin{aligned} \begin{aligned} &Dg\big(t,x,f_{1}(x)\big)=D_{x}g\big(t,x,f_{1}(x)\big)+D_{u}g\big(t,x,f _{1}(x)\big)\,Df_{1}(x), \qquad x\in [0,\infty ), \\ &Dg\big(t,x,f_{2}(x)\big)=D_{x}g\big(t,x,f_{2}(x)\big)+D_{v}g\big(t,x,f _{2}(x)\big)\,Df_{2}(x), \qquad x\in [0,\infty ). \end{aligned} \end{aligned}$$
Thus
$$\begin{aligned} &Dg\big(t,x,f_{1}(x)\big)-Dg\big(t,x,f_{2}(x)\big) \\ &=D_{x}g\big(t,x,f_{1}(x)\big)-D_{x}g\big(t,x,f_{2}(x)\big)+D_{u}g \big(t,x,f_{1}(x)\big)\big(Df_{1}(x)-Df_{2}(x)\big) \\ & \phantom{=:}+\Big(D_{u}g\big(t,x,f_{1}(x)\big)-D_{v}g\big(t,x,f_{2}(x) \big)\Big)\,Df_{2}(x), \qquad x\in [0,\infty ). \end{aligned}$$
Using the Cauchy–Schwarz inequality, we obtain
$$\begin{aligned} &\big\| Dg\big(t,x,f_{1}(x)\big)-Dg\big(t,x,f_{2}(x)\big)\big\| _{H} \\ &\leq \big\| D_{x}g\big(t,x,f_{1}(x)\big)-D_{x}g\big(t,x,f_{2}(x) \big)\big\| _{H} \\ & \phantom{=:}+\big\| D_{u}g\big(t,x,f_{1}(x)\big)\big\| _{H}|Df_{1}(x)-Df _{2}(x)| \\ & \phantom{=:}+\big\| D_{u}g\big(t,x,f_{1}(x)\big)-D_{v}g\big(t,x,f_{2}(x) \big)\big\| _{H}|Df_{2}(x)|. \end{aligned}$$
It follows from (
4.20)–(
4.22) that for
\(x\in [0, \infty )\),
$$\begin{aligned} &\big\| Dg\big(t,x,f_{1}(x)\big)-Dg\big(t,x,f_{2}(x)\big)\big\| _{H} \\ &\leq |D\hat{g}(x)|\,|f_{1}(x)-f_{2}(x)|+K_{1}|Df_{1}(x)-Df_{2}(x)| \\ & \phantom{=:}+K_{2}|f_{1}(x)-f_{2}(x)|\,|Df_{2}(x)|. \end{aligned}$$
(4.26)
Taking into account (
4.24) and the last inequality, we obtain for each
\(x\in [0,\infty )\) that
$$\begin{aligned} &\big|D\big(F(t,f_{1})(x)-F(t,f_{2})(x)\big)\big| \\ &\leq \|\hat{g}\|_{\infty }\|f_{1}-f_{2}\|_{1}|D\bar{g}(x)|+K_{1}\| \hat{g}\|_{\infty }\|f_{1}-f_{2}\|_{1}|Df_{1}(x)| \\ & \phantom{=:}+\|\bar{g}\|_{1}|D\hat{g}(x)||f_{1}(x)-f_{2}(x)|+K_{1}\| \bar{g}\|_{1}|Df_{1}(x)-Df_{2}(x)| \\ & \phantom{=:}+ K_{2}\|\bar{g}\|_{1}|f_{1}(x)-f_{2}(x)||Df_{2}(x)|+2| \bar{g}(x)||\hat{g}(x)||f_{1}(x)-f_{2}(x)|. \end{aligned}$$
Using the last inequality and Proposition
4.11, we infer that
$$\begin{aligned} &\big\| D\big(F(t,f_{1})-F(t,f_{2})\big)\big\| _{\nu ,p} \\ &\leq 6\|\hat{g}\|_{\infty }\|f_{1}-f_{2}\|_{1}\|D\bar{g}\|_{\nu ,p}+6K _{1}\|\hat{g}\|_{\infty }\|f_{1}-f_{2}\|_{1}\|Df_{1}\|_{\nu ,p} \\ & \phantom{=:}+6\|\bar{g}\|_{1}\|D\hat{g}\|_{\nu ,p}\|f_{1}-f_{2}\|_{ \infty }+6K_{1}\|\bar{g}\|_{1}\|Df_{1}-Df_{2}\|_{\nu ,p} \\ & \phantom{=:}+6K_{2}\|\bar{g}\|_{1}\|f_{1}-f_{2}\|_{\infty }\|Df_{2}\| _{\nu ,p}+6\|\hat{g}\|_{\infty }\|\bar{g}\|_{\infty }\|f_{1}-f_{2}\| ^{p}_{\nu ,p}. \end{aligned}$$
(4.27)
It follows from (
4.25) and (
4.27) that
\(F\) is Lipschitz on balls. □