The internal (contact) force
\(\mathbf {n}_{}{}\) and internal (contact) moment
\(\mathbf {m}_{}{}\), collectively called
stress resultants, are defined by:
$$\begin{aligned} \mathbf {n}_{}{}=n _i\mathbf {d}_{i}{},\quad \mathbf {m}_{}{}=m _i\mathbf {d}_{i}{}. \end{aligned}$$
(12)
Their rotational pull backs are
$$\begin{aligned} \begin{aligned} \mathbf {n}_{0}{}=n _i\mathbf {D}_{i},\quad \mathbf {m}_{0}{}=m _i\mathbf {D}_{i}. \end{aligned} \end{aligned}$$
(6)
For the elastic case and assuming the existence of a scalar-valued strain energy density function
\(\psi ^{rod }(\mathbf {v}_{0}^{}{}, \mathbf {k}_{0}^{}{})\) the
stress resultants follow as
$$\begin{aligned} \begin{aligned} \mathbf {n}_{0}{}=\frac{\partial \psi ^{rod }}{\partial \mathbf {v}_{0}^{}{}}(\mathbf {v}_{0}^{}{}, \mathbf {k}_{0}^{}{}),\quad \mathbf {m}_{0}{}=\frac{\partial \psi ^{rod }}{\partial \mathbf {k}_{0}^{}{}}(\mathbf {v}_{0}^{}{}, \mathbf {k}_{0}^{}{}). \end{aligned} \end{aligned}$$
(13)
The second derivative of
\(\psi ^{rod }(\mathbf {v}_{0}^{}{},\mathbf {k}_{0}^{}{})\) with respect to the
strain prescriptors yields the
\(6\times 6\) tangent stiffness
\(\mathbf {C}_0\)$$\begin{aligned} \begin{aligned} \mathbf {C}_0&= \begin{bmatrix} \mathbf {C}_{0_{vv }} &{} \mathbf {C}_{0_{vk }}\\ \mathbf {C}_{0_{kv }} &{} \mathbf {C}_{0_{kk }} \end{bmatrix}\\&= \begin{bmatrix} \displaystyle { \frac{\partial ^2\psi ^{rod }}{\partial \mathbf {v}_{0}^{}{}\partial \mathbf {v}_{0}^{}{}}\left( \mathbf {v}_{0}^{}{},\mathbf {k}_{0}^{}{}\right) } &{} \displaystyle {\frac{\partial ^2\psi ^{rod }}{\partial \mathbf {v}_{0}^{}{}\partial \mathbf {k}_{0}^{}{}}\left( \mathbf {v}_{0}^{}{},\mathbf {k}_{0}^{}{}\right) } \\ \displaystyle {\frac{\partial ^2\psi ^{rod }}{\partial \mathbf {k}_{0}^{}{}\partial \mathbf {v}_{0}^{}{}}\left( \mathbf {v}_{0}^{}{},\mathbf {k}_{0}^{}{}\right) } &{} \displaystyle {\frac{\partial ^2\psi ^{rod }}{\partial \mathbf {k}_{0}^{}{}\partial \mathbf {k}_{0}^{}{}}\left( \mathbf {v}_{0}^{}{},\mathbf {k}_{0}^{}{}\right) } \end{bmatrix}, \end{aligned} \end{aligned}$$
(14)
which relates the change in the
stress resultants to the change in the
strain prescriptors as
$$\begin{aligned} \begin{bmatrix} d {{\textbf {n}}}_0\\ d {{\textbf {m}}}_0 \end{bmatrix} =\mathbf {C}_0 \begin{bmatrix} d {{\textbf {v}}}_0 \\ d {{\textbf {k}}}_0 \end{bmatrix}. \end{aligned}$$
(15)
Assuming
\(\psi ^{rod }\) to be quadratic in the
strain prescriptors, a linear relation between
stress resultants and
strain prescriptors results
$$\begin{aligned} \begin{bmatrix} {{\textbf {n}}}_0\\ {{\textbf {m}}}_0 \end{bmatrix} =\mathbf {C}_0 \begin{bmatrix} {{\textbf {v}}}_0-\mathbf {E}_3 \\ {{\textbf {k}}}_0 \end{bmatrix}. \end{aligned}$$
(16)
In the elastoplastic case the definition of the
stress resultants (
13) is no longer valid. The key components of modeling elastoplastic rods are briefly presented here. The
strain prescriptors are assumed to decompose into an elastic and a plastic part as follows:
A free energy density function
\({\varPsi }^{rod } \) is introduced as
$$\begin{aligned} {\varPsi }^{rod } (\mathbf {v}_{0}^{e}{},\mathbf {k}_{0}^{e}{}, \varvec{\xi })=\psi ^{rod }(\mathbf {v}_{0}^{e}{},\mathbf {k}_{0}^{e}{}) +\mathcal {H}^{rod }(\varvec{\xi }), \end{aligned}$$
(18)
where
\(\psi ^{rod }(\mathbf {v}_{0}^{e}{},\mathbf {k}_{0}^{e}{})\) denotes the strain energy density and
\(\mathcal {H}^{rod }(\varvec{\xi })\) describes the resultant-type hardening depending on the internal variables
\(\varvec{\xi }\). The dissipation power
\(\mathcal {D}\) is the difference between the
stress resultants power and the material time derivative of the free energy density and must be positive:
$$\begin{aligned} \mathcal {D} =\mathbf {n}_0\cdot \dot{\mathbf {v}}_0+\mathbf {m}_0\cdot \dot{\mathbf {k}}_0-\frac{d {\varPsi }^{rod }}{d t}(\mathbf {v}_{0}^{e}{},\mathbf {k}_{0}^{e}{},\varvec{\xi })\ge 0, \end{aligned}$$
(19)
where
\(\displaystyle {\dot{\bullet }:=\left. \frac{d \bullet }{d t}\right| _{\mathbf {X}}}\). Computing the time derivative by applying chain rule and requiring that the result has to hold for any admissible process, one obtains the constitutive equations:
$$\begin{aligned} \mathbf {n}_0=\frac{\partial \psi ^{rod }}{\partial \mathbf {v}_{0}^{e}{}}(\mathbf {v}_{0}^{e}{},\mathbf {k}_{0}^{e}{}),\quad \mathbf {m}_0=\frac{\partial \psi ^{rod }}{\partial \mathbf {k}_{0}^{e}{}}(\mathbf {v}_{0}^{e}{},\mathbf {k}_{0}^{e}{}). \end{aligned}$$
(20)
Furthermore, the resultant-type hardening stress
\(\varvec{\beta }\) is defined as
$$\begin{aligned} \varvec{\beta }=-\frac{\partial \mathcal {H}^{rod }}{\partial \varvec{\xi }}(\varvec{\xi }). \end{aligned}$$
(21)
Inserting equations (
20) and (
21) into the dissipation inequality yields its reduced form
$$\begin{aligned} \mathcal {D}^{red}=\mathbf {n}_0\cdot \dot{\mathbf {v}}_0^p+\mathbf {m}_0\cdot \dot{\mathbf {k}}_0^p+\varvec{\beta }\cdot \dot{\varvec{\xi }}\ge 0. \end{aligned}$$
(22)
Expression (
22) is maximized under the constraint
\(\displaystyle {\varPhi }(\mathbf {n}_0,\mathbf {m}_0,\varvec{\beta })\le 0\). Here
\(\varPhi \) describes a yield-function in terms of
stress resultants. Finally, the evolution equations for the plastic quantities are obtained:
$$\begin{aligned} \begin{aligned}&\dot{\mathbf {v}}_0^p=\dot{\gamma }\frac{\partial \varPhi }{\partial \mathbf {n}_0}(\mathbf {n}_0,\mathbf {m}_0,\varvec{\beta }), \quad \dot{\mathbf {k}}_0^p=\dot{\gamma }\frac{\partial \varPhi }{\partial \mathbf {m}_0}(\mathbf {n}_0,\mathbf {m}_0,\varvec{\beta }), \quad \\&\dot{\varvec{\xi }}=\dot{\gamma }\frac{\partial \varPhi }{\partial \varvec{\beta }}(\mathbf {n}_0,\mathbf {m}_0,\varvec{\beta }). \end{aligned} \end{aligned}$$
(23)
Together with Karush-Kuhn-Tucker (KKT) conditions, the Lagrange multiplier
\(\dot{\gamma }\) ensures admissibility of the resulting
stress resultants$$\begin{aligned} \dot{\gamma }\ge 0,\quad \dot{\gamma }\,\varPhi (\mathbf {n}_0,\mathbf {m}_0,\varvec{\beta })=0,\quad \varPhi (\mathbf {n}_0,\mathbf {m}_0,\varvec{\beta })\le 0. \end{aligned}$$
(24)
The changes in
stress resultants are related to the changes in
strain prescriptors via the
\(6\times 6\) elastoplastic tangent stiffness
\(\mathbf {C}_0^{ep }\)$$\begin{aligned} \begin{bmatrix} d {{\textbf {n}}}_0\\ d {{\textbf {m}}}_0 \end{bmatrix} =\mathbf {C}_0^{ep } \begin{bmatrix} d {{\textbf {v}}}_0 \\ d {{\textbf {k}}}_0 \end{bmatrix}. \end{aligned}$$
(25)
Due to the additive nature of the
strain prescriptors, methods from small-strain plasticity may be applied to derive an update algorithm and the algorithmic elastoplastic tangent [
18]. Using a plasticity formulation in terms of
stress resultants is further called the
stress resultants approach to solve elastoplastic rods.