Choose
\(a>2t\) and let
\(x_{0}\in X_{\omega}\) be an arbitrary point. Since
\(S(X_{\omega})\subseteq h(X_{\omega})\), there is a point
\(x_{1}\in X_{\omega}\) such that
\(S(x_{0})=h(x_{1})\). On continuing this, we generate a sequence
\(\{hx_{n}\}_{n=1}^{\infty}\) as follows:
\(Sx_{n}=hx_{n+1}\) for each
n. Suppose for any
n,
\(hx_{n}\neq hx_{n+1}\), since, otherwise, there exists a point of coincidence of
S and
h, (3) shows that
$$\begin{aligned} \int_{0}^{\omega_{\lambda/a}(hx_{n+1}, h_{x_{n}})}\varphi(r)\,\mathrm {d}r&= \int _{0}^{\omega_{\lambda/a}(Sx_{n},Sx_{n-1})}\varphi(r)\,\mathrm {d}r \\ &\leq \int_{0}^{\mathcal{M}(x_{n},x_{n-1})}\varphi(r)\,\mathrm {d}r-\phi \biggl( \int _{0}^{\mathcal{M}(x_{n},x_{n-1})}\varphi(r)\,\mathrm {d}r \biggr), \end{aligned}$$
where
$$\begin{aligned} \mathcal{M}(x_{n},x_{n-1})=&\max \biggl\{ \omega_{\lambda /t}(hx_{n},hx_{n-1}), \omega_{\lambda/t}(hx_{n},Sx_{n}), \omega_{\lambda /t}(hx_{n-1},Sx_{n-1}), \\ &\frac{\omega_{\lambda /t}(hx_{n},Sx_{n-1})+\omega_{\lambda/t}(hx_{n-1},Sx_{n})}{2}, \frac{\omega_{\lambda/t}(hx_{n},Sx_{n-1})\omega_{\lambda /t}(hx_{n-1},Sx_{n})}{1+\omega_{\lambda/t}(hx_{n}, hx_{n-1})}, \\ &\frac {\omega_{\lambda/t}(hx_{n},Sx_{n})\omega_{\lambda/t}(hx_{n}, Sx_{n-1})}{2[1+\omega_{\lambda/t}(hx_{n}, hx_{n-1})]}, \frac{\omega_{\lambda/t}(hx_{n-1}, Sx_{n-1})\omega_{\lambda /t}(hx_{n-1}, Sx_{n})}{2[1+\omega_{\lambda/t}(hx_{n}, hx_{n-1})]} \biggr\} . \end{aligned}$$
Since
\(hx_{n}=Sx_{n-1}\), it follows that
$$\begin{aligned} \mathcal{M}(x_{n},x_{n-1})=&\max \biggl\{ \omega_{\lambda /t}(hx_{n-1},hx_{n}), \omega_{\lambda/t}(hx_{n}, hx_{n+1}), \frac{\omega _{\lambda/t}(hx_{n-1},hx_{n+1})}{2}, \\ &\frac{\omega_{\lambda /t}(hx_{n-1}, hx_{n})\omega_{\lambda/t}(hx_{n-1}, hx_{n+1})}{2[1+\omega _{\lambda/t}(hx_{n}, hx_{n-1})]} \biggr\} . \end{aligned}$$
Moreover,
$$\begin{aligned} \omega_{\lambda/t}(hx_{n-1},hx_{n+1}) &\leq \omega_{\lambda /2t}(hx_{n-1}, hx_{n})+\omega_{\lambda/2t}(hx_{n}, hx_{n+1}) \\ &\leq\omega_{\lambda/a}(hx_{n-1}, hx_{n})+ \omega_{\lambda/a}(hx_{n}, hx_{n+1}) \end{aligned}$$
and
$$\begin{aligned} \frac{\omega_{\lambda/t}(hx_{n-1}, hx_{n})\omega_{\lambda/t}(hx_{n-1}, hx_{n+1})}{2[1+\omega_{\lambda/t}(hx_{n}, hx_{n-1})]} &\leq\frac{\omega _{\lambda/t}(hx_{n-1}, hx_{n+1})}{2} \\ &\leq\frac{\omega_{\lambda/a}(hx_{n-1}, hx_{n})+\omega_{\lambda /a}(hx_{n}, hx_{n+1})}{2} \\ &\leq\max \bigl\{ \omega_{\lambda/a}(hx_{n-1}, hx_{n}), \omega_{\lambda /a}(hx_{n}, hx_{n+1}) \bigr\} , \end{aligned}$$
then
$$\mathcal{M}(x_{n},x_{n-1})\leq\max \bigl\{ \omega_{\lambda/a}(hx_{n-1}, hx_{n}), \omega_{\lambda/a}(hx_{n}, hx_{n+1}) \bigr\} . $$
Now if
\(\omega_{\lambda/a}(hx_{n}, hx_{n+1})> \omega_{\lambda /a}(hx_{n-1}, hx_{n})\), then
$$\begin{aligned} \int_{0}^{\omega_{\lambda/a}(hx_{n+1},hx_{n})}\varphi(r)\,\mathrm {d}r &\leq \int _{0}^{\omega_{\lambda/a}(hx_{n},hx_{n+1})}\varphi(r)\,\mathrm {d}r-\phi \biggl( \int _{0}^{\omega_{\lambda/a}(hx_{n},hx_{n+1})}\varphi(r)\,\mathrm {d}r \biggr) \\ &< \int_{0}^{\omega_{\lambda/a}(hx_{n},hx_{n+1})}\varphi(r)\,\mathrm {d}r. \end{aligned}$$
This is a contradiction. So,
\(\mathcal{M}(x_{n},x_{n-1})\leq\omega _{\lambda/a}(hx_{n-1}, hx_{n})\). Therefore
$$\begin{aligned} \begin{aligned}[b] \int_{0}^{\omega_{\lambda/a}(hx_{n+1},hx_{n})}\varphi(r)\,\mathrm {d}r &\leq \int _{0}^{\omega_{\lambda/a}(hx_{n},hx_{n-1})}\varphi(r)\,\mathrm {d}r-\phi \biggl( \int _{0}^{\omega_{\lambda/a}(hx_{n},hx_{n-1})}\varphi(r)\,\mathrm {d}r \biggr) \\ &< \int_{0}^{\omega_{\lambda/a}(hx_{n},hx_{n-1})}\varphi(r)\,\mathrm {d}r, \end{aligned} \end{aligned}$$
(2.1)
it shows that the sequence
\(\{\int_{0}^{\omega_{\lambda/a}(hx_{n+1}, hx_{n})}\varphi(r)\}\) is decreasing and bounded below. Hence, there is
\(k\geq0\) such that
$$\begin{aligned} \lim_{n\to\infty} \int_{0}^{\omega_{\lambda/a}(hx_{n+1},hx_{n})}\varphi (r)\,\mathrm {d}r=k. \end{aligned}$$
If
\(k>0\), then by Lemma
2.3 and (
2.1), we have a contradiction. So, we get
$$\begin{aligned} \lim_{n\to\infty}{\omega_{\lambda/a}(hx_{n+1},hx_{n})}=0. \end{aligned}$$
Suppose
\(l< a'<2t\), since
\(\omega_{\lambda}\) is a decreasing function, so
\(\omega_{\lambda/a'}(hx_{n+1},hx_{n})\leq\omega_{\lambda /a}(hx_{n+1}, hx_{n})\), whenever
\(a'<2t\leq a\). On considering the limit as
\(n\to\infty\) from both sides of this inequality shows that
\(\omega _{\lambda/a'}(hx_{n+1},hx_{n})\to0\) for
\(t< a'<2t\) and
\(\lambda>0\). Thus we have
\(\omega_{\lambda/a}(hx_{n+1},hx_{n})\to0\) as
\(n\to\infty\) for any
\(a>t\). Next, we show that
\(\{hx_{n}\}_{n\in\mathbb{N}}\) is a Cauchy sequence. So, for all
\(\varepsilon>0\), there exists
\(n_{0}\in \mathbb{N}\) such that
\(\omega_{\lambda/a}(hx_{n+1}, hx_{n})<\frac{\varepsilon}{a}\) for all
\(n\in\mathbb{N}\) with
\(n\geq n_{0}\) and
\(\lambda>0\). Suppose
\(m, n\in\mathbb{N}\) and
\(m > n\). Observe that, for
\(\frac{\lambda }{a(m-n)}\), there exists
\(n_{\frac{\lambda}{(m-n)}}\in\mathbb{N}\) such that
$$\begin{aligned} \omega_{\frac{\lambda}{a(m-n)}}(hx_{n+1},hx_{n})< \frac{\epsilon}{a(m-n)}, \end{aligned}$$
for all
\(n\geq n_{\frac{\lambda}{(m-n)}}\). Now, we have
$$\begin{aligned} \omega_{\lambda/l}(hx_{n}, hx_{m}) \leq& \omega_{\frac{\lambda }{a(m-n)}}(hx_{n}, hx_{n+1})+\omega_{\frac{\lambda }{a(m-n)}}(hx_{n+1},hx_{n+2})+\cdots+ \omega_{\frac{\lambda }{a(m-n)}}(hx_{m-1}, hx_{m}) \\ < & \frac{\varepsilon}{a(m-n)}+\frac{\varepsilon}{a(m-n)}+\cdots+\frac {\varepsilon}{a(m-n)} \\ =&\varepsilon/a, \end{aligned}$$
for all
\(m,n\geq n_{\frac{\lambda}{(m-n)}}\). This shows that
\(\{hx_{n}\} _{n\in\mathbb{N}}\) is a Cauchy sequence. From completeness of
\(h(X_{\omega})\), it follows that there exists
\(x^{*}\in X\) such that
\(\omega _{\lambda/t}(hx_{n},x^{*})\to0\) as
\(n\to\infty\). Consequently, we can find
p in
\(X_{\omega}\) such that
\(h(p)=x^{*}\). By (3), we get
$$\begin{aligned} \int_{0}^{\omega_{\lambda/a}(hx_{n}, Sp)}\varphi(r)\,\mathrm {d}r&= \int_{0}^{\omega _{\lambda/a}(Sx_{n-1}, Sp)}\varphi(r)\,\mathrm {d}r \\ &\leq \int_{0}^{\mathcal{M}(x_{n-1}, p)}\varphi(r)\,\mathrm {d}r-\phi \biggl( \int _{0}^{\mathcal{M}(x_{n-1}, p)}\varphi(r)\,\mathrm {d}r \biggr), \end{aligned}$$
where
$$\begin{aligned} \mathcal{M}(x_{n-1},p) =&\max \biggl\{ \omega_{\lambda/t}(hx_{n-1},hp), \omega_{\lambda/t}(hx_{n-1},Sx_{n-1}), \omega_{\lambda/t}(hp,Sp), \\ & \frac{\omega_{\lambda/t}(hx_{n-1},Sp)+\omega_{\lambda/t}(hp,Sx_{n-1})}{2}, \frac{\omega_{\lambda/t}(hx_{n-1},Sp)\omega_{\lambda /t}(hp,Sx_{n-1})}{1+\omega_{\lambda/t}(hx_{n-1}, hp)} \\ &\frac{\omega_{\lambda/t}(hx_{n-1},Sx_{n-1})\omega_{\lambda /t}(hx_{n-1},Sp)}{2[1+\omega_{\lambda/t}(hx_{n-1}, hp)]}, \frac{\omega_{\lambda/t}(hp,Sp)\omega_{\lambda /t}(hp,Sx_{n-1})}{2[1+\omega_{\lambda/t}(hx_{n-1}, hp)]} \biggr\} . \end{aligned}$$
By taking the limit as
\(n\to\infty\), we have
$$\begin{aligned} \int_{0}^{\omega_{\lambda/a}(x^{*}, Sp)}\varphi(r)\,\mathrm {d}r &\leq \int _{0}^{\omega_{\lambda/t}(x^{*}, Sp)}\varphi(r)\,\mathrm {d}r-\phi \biggl( \int _{0}^{\omega_{\lambda/t}(x^{*}, Sp)}\varphi(r)\,\mathrm {d}r \biggr) \\ & < \int_{0}^{\omega_{\lambda/t}(x^{*}, Sp)}\varphi(r)\,\mathrm {d}r \\ & \leq \int_{0}^{\omega_{\lambda/a}(x^{*}, Sp)}\varphi(r)\,\mathrm {d}r. \end{aligned}$$
This shows
\(\omega_{\lambda/a}(Sp,x^{*})= 0\) for
\(\lambda>0\). Hence
\(Tp=x^{*}\) and
S and
h have the point of coincidence
\(x^{*}\). Suppose that
\(q\neq x^{*}\) is another point of coincidence of
S and
h in
\(X_{\omega}\). Then
\(Tv=hv=q\) for some
v in
\(X_{\omega}\). By (3), we get
$$\begin{aligned} \int_{0}^{\omega_{\lambda/a}(hp,hv)}\varphi(r)\,\mathrm {d}r&= \int_{0}^{\omega _{\lambda/a}(Sp,Sv)}\varphi(r)\,\mathrm {d}r \\ &\leq \int_{0}^{\mathcal{M}(p,v)}\varphi(r)\,\mathrm {d}r-\phi \biggl( \int _{0}^{\mathcal{M}(p,v)}\varphi(r)\,\mathrm {d}r \biggr), \end{aligned}$$
where
$$\begin{aligned} \mathcal{M}(p,v) =&\max \biggl\{ \omega_{\lambda/t}(hp, hv), \omega _{\lambda/t}(hp, Sp), \omega_{\lambda/t}(hv, Sv), \\ & \frac{\omega_{\lambda/t}(hv, Sp)+\omega_{\lambda/t}(hp,Sv)}{2}, \frac{\omega_{\lambda/t}(hp,Sv)\omega_{\lambda/t}(hv,Sp)}{1+\omega _{\lambda/t}(hp, hv)}, \\ &\frac{\omega_{\lambda/t}(hp,Sp)\omega_{\lambda/t}(hp,Sv)}{2[1+\omega _{\lambda/t}(hp, hv)]}, \frac{\omega_{\lambda/t}(hv,Sv)\omega_{\lambda/t}(hv,Sp)}{2[1+\omega _{\lambda/t}(hp, hv)]} \biggr\} \\ =&\omega_{\lambda/t}(hp, hv). \end{aligned}$$