1 Introduction
2 Counterexample for Devi’s analysis
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\(\tau _1: (T_1=D_1=6, C_1=5, S_1=1)\) and
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\(\tau _2: (T_2=D_2=8, C_2=\epsilon , S_2=0)\), for any \(0 <\epsilon \le 1/3\).
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When \(k=1\), we have \(B_1 = 1\) and \(B_1'=0\). Therefore, when \(k=1\), we obtain \(\frac{B_k+B_k'}{T_k} + \sum _{i=1}^{k}\frac{C_i}{T_i} = 1\).
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When \(k=2\), we have \(B_2 = 1\) and \(B_2'=0\). Therefore, when \(k=2\), we obtain \(\frac{B_k+B_k'}{T_k} + \sum _{i=1}^{k}\frac{C_i}{T_i} = \frac{1}{8} + \frac{\epsilon }{8} + \frac{5}{6} = \frac{23+3\epsilon }{24} \le 1\), since \(\epsilon \le 1/3\).