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2014 | OriginalPaper | Chapter

23. Patent Licensing: Stackelberg Versus Cournot Models

Authors : Oana Bode, Flávio Ferreira

Published in: Discontinuity and Complexity in Nonlinear Physical Systems

Publisher: Springer International Publishing

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Abstract

In the present study we consider, on one hand, a differentiated Stackelberg model, and, on the other hand, a differentiated Cournot model, when one of the firms engages in an R & D process that gives an endogenous cost-reducing innovation. The aim of this study is two fold. The first is to study the licensing of the cost-reduction in the Stackelberg model. The second is to do a direct comparison between Stackelberg model and Cournot model. We analyse the implications of these types of licensing contracts over the R & D effort, the profits of the firms, the consumer surplus and the social welfare. By using comparative static analysis, we conclude that the degree of the differentiation of the goods assumes a great importance in the results.

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Footnotes
1
Throughout the paper we use the notation superscript S to refer to the Stackelberg competition.
 
2
We note that d 1 ≃ 0. 732.
 
3
Throughout the paper we use the notation subscript nl to refer to the pre-licensing case.
 
4
Throughout the paper we will add a ∼ to identify the values we get in the drastic innovation case.
 
5
We note that 0 < d2 < 1 is such that \(d_{2}^{2} - 4d_{2} + 1 = 0\) , i.e. d 2 ≃ 0.268.
 
6
We note that 0 < d3 < 1 is such that \(d_{3}^{4} + 2d_{3}^{3} + 8d_{3} - 8 = 0\) , i.e. d 3 ≃ 0.812.
 
7
We note that 0 < d4 < 1 is such that \(d_{4}^{4} - 5d_{4}^{3} - 3d_{4}^{2} + 10d_{4} - 2 = 0\) , i.e. d 4 ≃ 0.219.
 
8
We note that 0 < d5 < 1 is such that \(7d_{5}^{4} - 13d_{5}^{3} - 9d_{5}^{2} + 28d_{5} - 10 = 0\) , i.e. d 5 ≃ 0.458.
 
9
Throughout the paper, we use the notation subscript l to refer to the two-part tariff licensing case.
 
10
We note that 0 < d6 < 1 is such that \(6d_{6}^{6} - 42d_{6}^{5} + 125d_{6}^{4} - 156d_{6}^{3} + 14d_{6}^{2} + 112d_{6} - 56 = 0,\) i.e. d 6 ≃ 0.721.
 
11
We note that 0 < d7 < 1 is such that \(6d_{7}^{2} - 18d_{7} + 11 = 0,\) i.e. d 7 ≃ 0.855.
 
12
We note that 0 < d8 < 1 is such that \(54d_{8}^{10}-99d_{8}^{9}-621d_{8}^{8}+1866d_{8}^{7}-42d_{8}^{6}-4446d_{8}^{5}+3146d_{8}^{4}+3020d_{8}^{3}-3276d_{8}^{2}-344d_{8}+736 = 0,\) i.e. d 8 ≃ 0.863.
 
13
We note that d 10 ≃ 0. 747.
 
14
We note that d 11 ≃ 0. 828.
 
15
We note that d 12 ≃ 0. 928.
 
16
We note that d 13 ≃ 0. 941.
 
Literature
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Metadata
Title
Patent Licensing: Stackelberg Versus Cournot Models
Authors
Oana Bode
Flávio Ferreira
Copyright Year
2014
DOI
https://doi.org/10.1007/978-3-319-01411-1_23

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